1.
[tex] = {}^{3} \log(4) + {}^{3} \log(2)[/tex]
[tex] = {}^{3} \log(4 \times 2)[/tex]
[tex] = {}^{3} \log( {2}^{3} )[/tex]
[tex] = 3. {}^{3} \log(2)[/tex]
[tex] \: [/tex]
2.
[tex] = {}^{3} \log(12) - {}^{3} \log(2)[/tex]
[tex] = {}^{3} \log(12 \div 2)[/tex]
[tex] = {}^{3} \log(6)[/tex]
[tex] = {}^{3} \log(3 \times 2)[/tex]
[tex] = {}^{3} \log(3) + {}^{3} \log(2)[/tex]
[tex] = 1 + {}^{3} \log(2)[/tex]
[tex] \: [/tex]
3.
[tex] = {}^{8} \log(32) + {}^{8} \log(16) - {}^{8} \log(128)[/tex]
[tex] = {}^{8} \log(32 \times 16 \div 128)[/tex]
[tex] = {}^{8} \log(4)[/tex]
[tex] = {}^{ {2}^{3} } \log( {2}^{2} )[/tex]
[tex] = \frac{2}{3} \times {}^{2} \log(2)[/tex]
[tex] = \frac{2}{3} [/tex]
[tex] \: [/tex]
4.
[tex] = {}^{x} \log(5). {}^{5} \log(y) - {}^{y} \log(x)[/tex]
[tex] = {}^{x} \log(y). {}^{5} \log(5) - {}^{y} \log(x)[/tex]
[tex] = {}^{x} \log(y) - {}^{y} \log(x)[/tex]
[tex] \: [/tex]
5.
[tex] = {}^{3} \log(125)[/tex]
[tex] = {}^{3} \log( {5}^{3} )[/tex]
[tex] = 3. {}^{3} \log(5)[/tex]
Jawab:
Penjelasan dengan langkah-langkah:
[tex]^3log_4 + ^3log_2 = \ ^3log2^2 + \ ^3log_2\\^3log_4 + ^3log_2 = 2 \cdot \ ^3log_2 + \ ^3log_2\\^3log_4 + ^3log_2 = 3 \cdot\ ^3log_2\\\\[/tex]
[tex]^3log_{12} - \ ^3log_2 = \ ^3log_{\frac{12}{2}}\\^3log_{12} - \ ^3log_2 = \ ^3log_6\\\\^8log_{32} + \ ^8log_{16} - \ ^8log{128} = \ ^8log2^5 + \ ^8log2^4 - \ ^8log{2^7}\\^8log_{32} + \ ^8log_{16} - \ ^8log{128} = 5 \cdot\ ^8log2 + 4 \cdot \ ^8log2 - 7 \cdot \ ^8log2\\^8log_{32} + \ ^8log_{16} - \ ^8log{128} = \ ^8log2 (5+4-7)\\^8log_{32} + \ ^8log_{16} - \ ^8log{128 = 2 \cdot \ ^8log2\\\\[/tex]
[tex]^xlog_5\cdot \ ^5log_y\cdot \ ^ylog_x = \ ^xlog_5 \cdot \ ^5log_x\\^xlog_5\cdot \ ^5log_y\cdot \ ^ylog_x = \ ^xlog_x = 1\\\\^3 log_{125} = \ ^3log5^3\\^3 log_{125} = 3 \cdot \ ^3log 5[/tex]
[answer.2.content]
